Asked by Joy

one diagonal of a cyclic quadrilateral coincides with a diameter of a circle whose area is 36pi cm^2. If the other diagonal which measures 8cm meets the first diagonal at right angles, find the area of quadrilateral. Show your solutions
Answered by Steve
The diameter of the circle is 12 cm.

The quadrilateral consists of two congruent triangles, with base 12 and altitude 4. So, its area is 48 cm^2
Answered by Anonymous
How did you got your answer. I need a complete solution please.
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