Asked by Lyndsay

find the point on the plane 5x+4y+z=12 that is nearest to (2,0,1)

Answers

Answered by Steve
just use the usual distance formula. The distance between (a,b,c) and Ax+By+Cz+D=0 is

|Aa+Bb+Cc+D|/√(A^2+B^2+C^2)
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