Asked by Lyndsay
find the point on the plane 5x+4y+z=12 that is nearest to (2,0,1)
Answers
Answered by
Steve
just use the usual distance formula. The distance between (a,b,c) and Ax+By+Cz+D=0 is
|Aa+Bb+Cc+D|/√(A^2+B^2+C^2)
|Aa+Bb+Cc+D|/√(A^2+B^2+C^2)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.