Question
find the point on the plane 5x+4y+z=12 that is nearest to (2,0,1)
Answers
Steve
just use the usual distance formula. The distance between (a,b,c) and Ax+By+Cz+D=0 is
|Aa+Bb+Cc+D|/√(A^2+B^2+C^2)
|Aa+Bb+Cc+D|/√(A^2+B^2+C^2)