Asked by Anonymous
A point is moving in a plane in such a way that its distance from the point(3,0)is 1.5 times its distance from the straight line 3x-4=0.find the louces of the point and identify the conic.
Answers
Answered by
Reiny
let the point be P(x,y)
√((x-3)^2+y^2) = 1.5(x-4/3)
square both sides
(x-3)^2 + y^2 = (9/4)(x^2 - 8x/3 + 16/9)
x^2 - 6x + 9 + y^2 = 9x^2/4 - 6x + 4
4x^2 - 24x + 36 + 4y^2 = 9x^2 - 24x + 16
5x^2 - 4y^2 = 20
or x^2 /4 - y^2 /5 = 1 , which is a hyperbola
check my arithmetic
√((x-3)^2+y^2) = 1.5(x-4/3)
square both sides
(x-3)^2 + y^2 = (9/4)(x^2 - 8x/3 + 16/9)
x^2 - 6x + 9 + y^2 = 9x^2/4 - 6x + 4
4x^2 - 24x + 36 + 4y^2 = 9x^2 - 24x + 16
5x^2 - 4y^2 = 20
or x^2 /4 - y^2 /5 = 1 , which is a hyperbola
check my arithmetic
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.