Question

What point on the x-y plane does theta = 0 describe?

I tried doing:

tan(theta) = y/x
tan(0rad) = y/x
0 = y/x
So y is definitely 0.

y = rsin(theta)
r = y/sin(theta)
= 0/sin(0rad)
= 0/0
... I highly doubt that this problem was meant for having to do L'Hopital's rule, so I'm not sure what to do here. Thanks for any help in advance.

Answer 1

Do you mean "at what points does the sin of theta equal zero"?

If so, sin(Theta) = Y/r. Then sine of theta is zero at every point where Y equals zero: 0, 180, and 360o.