Question
What point on the x-y plane does theta = 0 describe?
I tried doing:
tan(theta) = y/x
tan(0rad) = y/x
0 = y/x
So y is definitely 0.
y = rsin(theta)
r = y/sin(theta)
= 0/sin(0rad)
= 0/0
... I highly doubt that this problem was meant for having to do L'Hopital's rule, so I'm not sure what to do here. Thanks for any help in advance.
I tried doing:
tan(theta) = y/x
tan(0rad) = y/x
0 = y/x
So y is definitely 0.
y = rsin(theta)
r = y/sin(theta)
= 0/sin(0rad)
= 0/0
... I highly doubt that this problem was meant for having to do L'Hopital's rule, so I'm not sure what to do here. Thanks for any help in advance.
Answers
Henry
Do you mean "at what points does the sin of theta equal zero"?
If so, sin(Theta) = Y/r. Then sine of theta is zero at every point where Y equals zero: 0, 180, and 360o.
If so, sin(Theta) = Y/r. Then sine of theta is zero at every point where Y equals zero: 0, 180, and 360o.