Asked by @@prit
given the quadratic equation expression x^2+10*x+12 find the turning point of its graph by using the technique known as completing the square.
Answers
Answered by
Reiny
let y = x^2 + 10x + 12
= (x^2 + 10x <b>+ 25 - 25</b>) + 12
= ( (x+5)^2 - 25) + 12
= (x+5)^2) - 25 + 12
= (x+5)^2 - 13
we have found the vertex to be (-5,-13), which for a parabola would be the turning point.
= (x^2 + 10x <b>+ 25 - 25</b>) + 12
= ( (x+5)^2 - 25) + 12
= (x+5)^2) - 25 + 12
= (x+5)^2 - 13
we have found the vertex to be (-5,-13), which for a parabola would be the turning point.
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