Asked by Emzkidinn.tk

A spring of natural length 1.5m is extended 0.0050m by a force of 0.8N, what will its length be when the applied force is 3.2N?

9 years ago

Answered by Henry

k = 0.8N/0.0050m = 160 N/m.

L = 1.5 + 3.5N*1m/160N. = 1.5219 m.

9 years ago

Answered by praise

2*2356nm

9 years ago

Answered by FUNKE

19.936

7 years ago

Answered by AMARACHI

I the school.

5 years ago

Answered by AMARACHI

I like this school. because it is good school.

5 years ago

Answered by Lialian

I don't understand

4 years ago

Answered by ace

thanks

3 years ago

Answered by Cent

It's good but the works is not clear

3 years ago

Answered by Uche

Chukwu

3 years ago

Answered by Emmanuel

Thanks for your help

3 years ago

Answered by AMINAT

THANKS

3 years ago

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