Asked by Amelia
Why is there no vertical asymptote on
F(x) = x/(x^2+1)
What i learned is that to find vertical asymptote you have to set the denominator To 0 and solve for x ?
In that case I find that x=-1,1
F(x) = x/(x^2+1)
What i learned is that to find vertical asymptote you have to set the denominator To 0 and solve for x ?
In that case I find that x=-1,1
Answers
Answered by
Steve
vertical asymptotes occur when you try to divide by zero.
x^2+1 is never zero.
You solved for x^2-1 = 0
x^2+1 is never zero.
You solved for x^2-1 = 0
Answered by
Amelia
I don't get it ?
Answered by
Steve
huh? huh? How can you say that?
x^2 is always positive, right? At least it is never negative.
So, x^2+1 is always positive, and always at least 1.
So, dividing by x^2+1 will never yield a vertical asymptote.
x^2 is always positive, right? At least it is never negative.
So, x^2+1 is always positive, and always at least 1.
So, dividing by x^2+1 will never yield a vertical asymptote.
Answered by
Amelia
Yesss okay thank you sir