Question

When looking for the vertical asymptote in for example, 1/(x^2+3), would the vertical asymptote be radical 3 or just there isn't one?

Answer 1

x^2 = -3
x = +/- sqrt (-3)
which is the imaginary number (sqrt 3)i
In other words, there is no real number solution.
Try graphing this function.
You will get a hump of height 1/3 at x = 0 and it will drop off toward zero on both sides of x = 0