Asked by Tristan
Find the equation of the asymptotes for the hyperbola defined by the equation:
((y + 4)^2 / 36) - ((x - 3)^2 / 25) = 1
((y + 4)^2 / 36) - ((x - 3)^2 / 25) = 1
Answers
Answered by
Reiny
centre is (-4,3)
and the asymptotes go through the centre
slopes are -5/6
y = (5/6)x + b
at (-4,3)
3 = (5/6)(-4) + b
b = 39/5
y = (5/6)x + 39/5
or
y = (-5/6)x + b
3 = (-5/6)(-4) + b
b = -1/3
y = (-5/6)x - 1/3
and the asymptotes go through the centre
slopes are -5/6
y = (5/6)x + b
at (-4,3)
3 = (5/6)(-4) + b
b = 39/5
y = (5/6)x + 39/5
or
y = (-5/6)x + b
3 = (-5/6)(-4) + b
b = -1/3
y = (-5/6)x - 1/3
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