Asked by Jen

Given that x=log3^5 and y=log3^2, rewrite log3^60 in terms of x and y.

Answers

Answered by Damon
60 = 5 * 2 * 3 * 2

60 = 2^2 * 5^1 * 3^1

log3(60)=log3(3)+log3(5)+2log3(2)

we know log3(3) = 1
so
log3(60) = 1 + x + 2y
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