Asked by Karen
A ball is thrown with a horizontal velocity of 2 m/s from a vertical height of 50 m above ground. neglect air resistance and determine:
the horizontal displacement traveled by the ball. can someone please explain this to me!
the horizontal displacement traveled by the ball. can someone please explain this to me!
Answers
Answered by
bobpursley
One needs to find how long it is in the air, the initial height determines that.
h=1/2 g t^2
Then, knowing the time in air, the horizontal distance is
d=vhorizontal*time
h=1/2 g t^2
Then, knowing the time in air, the horizontal distance is
d=vhorizontal*time
Answered by
Karen
Thanks!! Could you explain this one to me?
object is projected with a horizontal velocity of 30 m/s. if it hits the ground 5 seconds later, calculate:
The height from which the particle was projected.
object is projected with a horizontal velocity of 30 m/s. if it hits the ground 5 seconds later, calculate:
The height from which the particle was projected.
Answered by
bobpursley
h=1/2 g t^2
memorize that equation.
calculate height.
memorize that equation.
calculate height.
Answered by
Karen
thanks!
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