Asked by Josh
A rock is thrown with a horizontal speed of 50 m/s forward from a bridge. The rock reaches the water below 4 seconds later. Let up and forward be considered positive.
(a) What is the horizontal component of the rock's velocity when it reaches the water? (answer should be in m/s)
(b) What is the vertical component of the rock's velocity when it reaches the water? (answer should be in m/s)
(c) What is the speed of the rock when it reaches the water?(answer should be in m/s)
[Use = 10 m/s2]
(a) What is the horizontal component of the rock's velocity when it reaches the water? (answer should be in m/s)
(b) What is the vertical component of the rock's velocity when it reaches the water? (answer should be in m/s)
(c) What is the speed of the rock when it reaches the water?(answer should be in m/s)
[Use = 10 m/s2]
Answers
Answered by
Anonymous
The horizontal velocity component is CONSTANT. There is no horizontal force so no change in horizontal velocity.
h = Hi - 5 t^2
0 = Hi - 5 (16)
Hi = 80 meters high
v = -10 t = -10 * 4 = about -40 m/s
speed at ground = sqrt( 50^2 + 40^2)
h = Hi - 5 t^2
0 = Hi - 5 (16)
Hi = 80 meters high
v = -10 t = -10 * 4 = about -40 m/s
speed at ground = sqrt( 50^2 + 40^2)
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