Asked by Hansel
Two workers, if they were working together, could finish a certain job in 12 days. If one of the workers does the first half of the job and then the other one does the second half, the job will take them 25 days. How long would it take each worker to do the entire job by himself?
Answers
Answered by
bobpursley
combined rate=job/12days
rate1=.5job/Time1
rate2=.5job/(25-time1)
rate=rate1+rate2
job/12=.5job/time1+.5job/(25-time1)
looking for time1 t.
t(25-t)=6(25-t)+6(t)
25t-t^2-150=0
t^2-25t+150
(t-10)(t-15)=0
t=10, 15
and if you look at the second worker, time=25-t...
so the two workers can finish in 10 hours for one, 15hours for the other.
rate1=.5job/Time1
rate2=.5job/(25-time1)
rate=rate1+rate2
job/12=.5job/time1+.5job/(25-time1)
looking for time1 t.
t(25-t)=6(25-t)+6(t)
25t-t^2-150=0
t^2-25t+150
(t-10)(t-15)=0
t=10, 15
and if you look at the second worker, time=25-t...
so the two workers can finish in 10 hours for one, 15hours for the other.
Answered by
Dotty
110
Two workers, if they were working together, could finish a certain job in 12 days. If one of the workers does the first half of the job and then the other one does the second half, the job will take them 25 days. How long would it take each worker to do the entire job by himself?
Answer
Two workers, if they were working together, could finish a certain job in 12 days. If one of the workers does the first half of the job and then the other one does the second half, the job will take them 25 days. How long would it take each worker to do the entire job by himself?
Answer
Answered by
Me
Its 20 and 30
Answered by
Hannah
it would take 40 days and 60 days
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