Asked by Karen
a guy throws a ball up and catches it 3.5 seconds later. what is the max height and initial velocity.
Please help!
Please help!
Answers
Answered by
bobpursley
consider that the final veloicty is the negative of the intial velocity...
Vf=Vi+gt
2Vi=gt
vi=1/2 gt solve for vi
h= vit-1/2 g t^2 and use t=3.5/2 for time to get to max height.
Vf=Vi+gt
2Vi=gt
vi=1/2 gt solve for vi
h= vit-1/2 g t^2 and use t=3.5/2 for time to get to max height.
Answered by
Bobby
4 meters
Answered by
Bobby
4 meters 8 m/s
Answered by
S
17.16m/s and the displacement is 15meters
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