Question
a guy throws a ball up and catches it 3.5 seconds later. what is the max height and initial velocity.
Please help!
Please help!
Answers
bobpursley
consider that the final veloicty is the negative of the intial velocity...
Vf=Vi+gt
2Vi=gt
vi=1/2 gt solve for vi
h= vit-1/2 g t^2 and use t=3.5/2 for time to get to max height.
Vf=Vi+gt
2Vi=gt
vi=1/2 gt solve for vi
h= vit-1/2 g t^2 and use t=3.5/2 for time to get to max height.
Bobby
4 meters
Bobby
4 meters 8 m/s
S
17.16m/s and the displacement is 15meters