Asked by Anonymous

At the end of Summer, Puss discovers that his radiator antifreeze solution has dropped below the safe level. If the radiator contains 4 gallons of a 25% antifreeze solution, how many gallons of pure antifreeze must he add to bring it up to a desired 50% solution? how to solve this and please solution

Answers

Answered by Reiny
Let the amount of old stuff drained by x gallons
so you have 4-x gallons left of 25% solution

.25(4-x) + x = .5(4)
1 - .25x + x = 2
.75x = 1
(3/4)x = 1
x = 4/3

so drain 4/3 gallon of the current solution, then top it up with pure antifreeze
Answered by Anonymous
thanks you sooooooooooo much!
Answered by Anonymous
i do not think that the answer to this question is 4/3 the quoins asks

how many gallons of pure antifreeze must he add to bring it up to a desired 50% solution?
Answered by Anonymous
can someone please find the right answer plz plz plz
Answered by John
The new capacity is 4+x=y
Where x is the pure anti-freeze,
y is the total capacity.

4+x=y
0.25(4)+x=0.5y

1+x=2+0.5x
x=2

He needs to add 2 gallons of pure anti-freeze.
Answered by Anonymous
thanks
Answered by JEFFY
NO THE RIGHT ANSWER IS 69 OR 420
Answered by Anonymous
No 2 gallons is the correct answer.
Answered by jishka
Idk pls help
Answered by ????
No, its 2
Answered by Rago
its 2.
Answered by Me
The answer is 2
Answered by Anonymous
its 2
Answered by anna
its 2 :)
Answered by anoymous
it's right genius answer right there
Answered by CoolGirl
The correct answer is definitely 2. John is absolutely correct.
Answered by Abhav
I'm giving everyone who said 2 gallons a thumbs up!!! correct!!!
Answered by Anya
Yep 2 gallons is 100% correct
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Answered by Dhruva
It has to be 2
Answered by Broski
Dude the answer is 2 bro
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