At the end of Summer, Puss discovers that his radiator antifreeze solution has dropped below the safe level. If the radiator contains 4 gallons of a 25% antifreeze solution, how many gallons of pure antifreeze must he add to bring it up to a desired 50% solution? how to solve this and please solution

Let the amount of old stuff drained by x gallons

so you have 4-x gallons left of 25% solution

.25(4-x) + x = .5(4)
1 - .25x + x = 2
.75x = 1
(3/4)x = 1
x = 4/3

so drain 4/3 gallon of the current solution, then top it up with pure antifreeze

thanks you sooooooooooo much!

i do not think that the answer to this question is 4/3 the quoins asks

how many gallons of pure antifreeze must he add to bring it up to a desired 50% solution?

can someone please find the right answer plz plz plz

The new capacity is 4+x=y

Where x is the pure anti-freeze,
y is the total capacity.

4+x=y
0.25(4)+x=0.5y

1+x=2+0.5x
x=2

He needs to add 2 gallons of pure anti-freeze.

thanks

NO THE RIGHT ANSWER IS 69 OR 420

No 2 gallons is the correct answer.

Idk pls help

No, its 2

its 2.

The answer is 2

its 2

its 2 :)

it's right genius answer right there

The correct answer is definitely 2. John is absolutely correct.

I'm giving everyone who said 2 gallons a thumbs up!!! correct!!!

Yep 2 gallons is 100% correct

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It has to be 2

Dude the answer is 2 bro