Asked by Anik

A number consists of 3 digits whose sum 9,when digits are reversed, the number decreased by 198 .the
number is ...?
thanks

Answers

Answered by Steve
If the digits are a,b,c
a+b+c=9
100a+10b+c - 198 = 100c+10b+a

The numbers 351, 432 and 513 all work
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