Ask a New Question

Question

A number consists of 3 digits whose sum 9,when digits are reversed, the number decreased by 198 .the
number is ...?
thanks
9 years ago

Answers

Steve
If the digits are a,b,c
a+b+c=9
100a+10b+c - 198 = 100c+10b+a

The numbers 351, 432 and 513 all work
9 years ago

Related Questions

A number consists of two digits. The sum of twice the tens digit an 5 times the units digit is 19. I... a number consists of 2 digits whose sum is 8,if 18 is added to the number its digits are reversed ,f... A no consists of 2 digits whose product is 18 when 27 is subtracted from the no the digit inter chan... a number consists of 7 digits and the sum of all digits is one.what is the number? a number consists of two digits whose sum is 9. if 45 is subtracted from the number its digits are i... A number consists of two digits whose sum is 9. if three times the number is equal to eight times th... A number consists of two digits.THe digit in tens place is twice that in units place.if 18 is subtra... a number consists of two digits whose sum is 9. If three times the number is equal to eight times th...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use