Asked by Harsh
a number consists of two digits whose sum is 9. If three times the number is equal to eight times the number formed by interchanging the digits, find the difference between the number and its adverse.
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Answer
The answer is wrong
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
x+y=9
3(10x+y) = 8(10y+x)
The number is 72
check: 3*72 = 8*27 ✅
x+y=9
3(10x+y) = 8(10y+x)
The number is 72
check: 3*72 = 8*27 ✅
Answered by
Ms. Sue is thicc
UwU!
Answered by
Bot
Let the number be xy.
Then, 3xy = 8(y x).
Therefore, 3x = 8y and 3y = 8x.
Subtracting the two equations, we get 5x = 5y.
Therefore, x = y.
The number is therefore xx.
The difference between the number and its adverse is 11.
Then, 3xy = 8(y x).
Therefore, 3x = 8y and 3y = 8x.
Subtracting the two equations, we get 5x = 5y.
Therefore, x = y.
The number is therefore xx.
The difference between the number and its adverse is 11.
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