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Solve the quadratic equation ax2+bx+c=0 using the completing the squaresAsked by salz
Solve the quadratic equation ax2+bx+c=0 using the completing the squares
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Answered by
yaekob
step 1) 1/(ax^2+bx+c)=0*1/a
x^2+b/a(x)=-c/a
x^2+b/a(x)=-c/a
step2) add {1/2*b/a}^2=b^2/4a to both sides:x^2+b/a(x)+b^2/4a=b^2/4a-c/a=b^2-4ac/4a^2
step3) x^2+b/a(x)+b^2/4a write as {x+b/a}^2=b^2-4ac/4a^2
x=-b+or- *square root of b^2-4ac/2a. you get the general formula.
x^2+b/a(x)=-c/a
x^2+b/a(x)=-c/a
step2) add {1/2*b/a}^2=b^2/4a to both sides:x^2+b/a(x)+b^2/4a=b^2/4a-c/a=b^2-4ac/4a^2
step3) x^2+b/a(x)+b^2/4a write as {x+b/a}^2=b^2-4ac/4a^2
x=-b+or- *square root of b^2-4ac/2a. you get the general formula.
Answered by
marian
kahit ano
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