Asked by Lucy

Find the equation of the hyperbola whose vertices are at (-1,-5) and (-1,1) with a focus at (-1,-7).

So far I have the center at (-1,-2) and part of the equation is (y+2)^2 - (x+1)^2 but do not know how to figure a^2, b^2, or c^2.

Help please....
Answered by bobpursley
Hmmm. I don't know what you mean by c.

(y+2)<sup>2</sup>/a<sup>2</sup> -(x+1)<sup>2</sup>/b<sup>2</sup> = 1

You have two points for x,y, that should give you two equation to solve for a, b.
Answered by Damon
center to vertex = a = 3
center to focus = sqrt(a^2+b^2) = 5
so 9+b^2 = 25
b = 4
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