Question
A car moving with a speed of 180km/h was brought uniformly to rest by the application of the breaks in 20s. How far did the car travel after the breaks were applied?
Answers
Scott
there are 3600 s in an hr
180 km/h = 50 m/s
the average velocity during the stop is ... (50 + 0) / 2
the stopping distance is
... 25 m/s * 20 s
180 km/h = 50 m/s
the average velocity during the stop is ... (50 + 0) / 2
the stopping distance is
... 25 m/s * 20 s
Michelle
Answers are not shown in a full working
Anonymous
Finial velocity = v= 0. t= 20s s=(v+u)/2 ×20s 180km/hrs = 50m/h s={0+50)/2×20 = 500