A car moving with a speed of 180km/h was brought uniformly to rest by the application of the breaks in 20s. How far did the car travel after the breaks were applied?

Answer 1

there are 3600 s in an hr

180 km/h = 50 m/s

the average velocity during the stop is ... (50 + 0) / 2

the stopping distance is
... 25 m/s * 20 s

Answer 2

Answers are not shown in a full working

Answer 3

Finial velocity = v= 0. t= 20s s=(v+u)/2 ×20s 180km/hrs = 50m/h s={0+50)/2×20 = 500