Asked by Coco

A car moving with a speed of 180km/h was brought uniformly to rest by the application of the breaks in 20s. How far did the car travel after the breaks were applied?

Answers

Answered by Scott
there are 3600 s in an hr

180 km/h = 50 m/s

the average velocity during the stop is ... (50 + 0) / 2

the stopping distance is
... 25 m/s * 20 s
Answered by Michelle
Answers are not shown in a full working
Answered by Anonymous
Finial velocity = v= 0. t= 20s s=(v+u)/2 ×20s 180km/hrs = 50m/h s={0+50)/2×20 = 500
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