Asked by MM
A car is moving with a speed of 22 m/s. The driver then brakes, and the car comes to a halt after 6.5 s. What is the distance covered by the car after the driver brakes, until it comes to a stop?
a. 36 m
b. 72 m
c. 140 m
d. 219 m
a. 36 m
b. 72 m
c. 140 m
d. 219 m
Answers
Answered by
Reiny
acceleration --- (-a)
velocity = -at + c
when t = 0, v = 22
22= 0+c ---> c = 0
v = -at + 22
when t = 6.5, v = 0
0 = -6.5a + 22
a = 22/6.5 = 44/13
distance = d = (-1/2)a t^2 + 22t + k
d = (-22/13)t^2 + 22t + k
when t = 0, d = 0, so k = 0
when t = 0 , d = 0
when t = 6.5, d = (-22/13)(6.5)^2 + 22(6.5)
= 71.5 m
looks like they rounded it off to 72 m
velocity = -at + c
when t = 0, v = 22
22= 0+c ---> c = 0
v = -at + 22
when t = 6.5, v = 0
0 = -6.5a + 22
a = 22/6.5 = 44/13
distance = d = (-1/2)a t^2 + 22t + k
d = (-22/13)t^2 + 22t + k
when t = 0, d = 0, so k = 0
when t = 0 , d = 0
when t = 6.5, d = (-22/13)(6.5)^2 + 22(6.5)
= 71.5 m
looks like they rounded it off to 72 m
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