speed of second train ---- x mph
speed of first train --- 2x-10 mph
When they meet they would have traveled the same time
let that time be t hrs
distance gone by first train = tx
distance gone by 2nd train = t(2x-1)
tx + t(2x-1) = 220
tx + 2tx - t = 220
t(3x-1)=220
t = 220/(3x-1)
I don't think we have enough information, since I can pick different values for x , and get valid answers
e.g. let x = 20 mph
then t = 220/(59) = 3.7288 hrs
then they meet after tx or 74.57 miles
the other distance is t(2x-1) = 145.42
they add up to 119.99 miles
e.g. let x = 40 mph
then t = 220/119 = 1.8487.. hrs
distance = 73.95 miles
etc
Two trains, one going from Boston to New York and the other going from New York to Boston, started their trips at exactly same time. Speed of the first train was 10 miles per hour less than twice the speed of the second train. How far from Boston station have they met, if the total distance between the cities along the rail road is 220 miles?
3 answers
140
just waking up in the morning gotta thank god, I dont know but today seems kinda odd