Question
An aeroplane at an height of 1 km is flying horizontally at 800 km/hr passes directly over an observer .find the rate at which it is approaching the observer when it is 1250 m away from him
Answers
h = 1000
x = sqrt (1250^2 - 1000^2)
= 750 meters horizontal
r = distance (hypotenuse)
r^2 = h^2 + x^2
2 r dr/dt = 0 + 2 x dx/dt
so
dr/dt = (x/r) dx/dt
= (750/1250)(800)
x = sqrt (1250^2 - 1000^2)
= 750 meters horizontal
r = distance (hypotenuse)
r^2 = h^2 + x^2
2 r dr/dt = 0 + 2 x dx/dt
so
dr/dt = (x/r) dx/dt
= (750/1250)(800)
Ans is 480 km per second..
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