500m/10 seconds
= 50m/second
An aeroplane is taking off from landing field has to run 500 metres.it leaves the ground in 10 seconds.what is the acceleration?
2 answers
since the distance covered by constant acceleration a is
s = 1/2 at^2, we have
1/2 a*10^2 = 500
a = 10 cm/s^2
50 m/s is the average speed during takeoff, not the acceleration.
s = 1/2 at^2, we have
1/2 a*10^2 = 500
a = 10 cm/s^2
50 m/s is the average speed during takeoff, not the acceleration.
2 answers