Asked by Emily
A 4.96 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=13.7N at an angle theta=16.0degrees above the horizontal. What is the magnitude of the acceleration of the block when the force is applied?
I know a=F/m
I know a=F/m
Answers
Answered by
Scott
the horizontal component of the force is... f cos(Θ)
as you say... a = [f cos(Θ)] / m
as you say... a = [f cos(Θ)] / m
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