Asked by jessie
                A 4.5 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=13.50 N at an angle theta=30.0 degrees above the horizontal. What is the speed of the block 5.50 seconds after it starts moving?
            
            
        Answers
                    Answered by
            Damon
            
    Fhorizontal = 13.5 cos 30
m a = 13.5 cos 30
a = (13.5/4.5) cos 30
v = a t
v = [(13.5/4.5) cos 30 ] (5.5)
    
m a = 13.5 cos 30
a = (13.5/4.5) cos 30
v = a t
v = [(13.5/4.5) cos 30 ] (5.5)
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