Asked by jessie
A 4.5 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=13.50 N at an angle theta=30.0 degrees above the horizontal. What is the speed of the block 5.50 seconds after it starts moving?
Answers
Answered by
Damon
Fhorizontal = 13.5 cos 30
m a = 13.5 cos 30
a = (13.5/4.5) cos 30
v = a t
v = [(13.5/4.5) cos 30 ] (5.5)
m a = 13.5 cos 30
a = (13.5/4.5) cos 30
v = a t
v = [(13.5/4.5) cos 30 ] (5.5)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.