Asked by jessie
A 4.5 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=13.50 N at an angle theta=30.0 degrees above the horizontal. What is the speed of the block 5.50 seconds after it starts moving?
Answers
Answered by
Damon
Fhorizontal = 13.5 cos 30
m a = 13.5 cos 30
a = (13.5/4.5) cos 30
v = a t
v = [(13.5/4.5) cos 30 ] (5.5)
m a = 13.5 cos 30
a = (13.5/4.5) cos 30
v = a t
v = [(13.5/4.5) cos 30 ] (5.5)