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A 50 g sample of an unknown metal is heated to 90.0C. It is placed in a perfectly insulated container along with 100 g of water...Asked by Anonymous
A 50 g sample of an unknown metal is heated to 90.0C. It is placed in a perfectly insulated container along with 100 g of water at an initial temperature of 20C. After a short time, the temperature of both the metal and water become equal at 25C. The specific heat of water is 4.18 J/gC in this temperature range. What is the specific heat capacity of the metal?
Record your answer with two significant figures.
Record your answer with two significant figures.
Answers
Answered by
bobpursley
The sum of the heats gained is zero.
Heatgainedwater+heatgainedmetal=0
100*cw*(25-20)+50(cmetal)(25-90)=0
solve for cmetal.
Heatgainedwater+heatgainedmetal=0
100*cw*(25-20)+50(cmetal)(25-90)=0
solve for cmetal.
Answered by
kkkkkkkkkkk
nokmkmkm
Answered by
kkkkkkkkkkk
A 50 g sample of an unknown metal is heated to 90.0C. It is placed in a perfectly insulated container along with 100 g of water at an initial temperature of 20C. After a short time, the temperature of both the metal and water become equal at 25C. The specific heat of water is 4.18 J/gC in this temperature range. What is the specific heat capacity of the metal?
Record your answer with two significant figures.
J/gC?????????????????????????????????????????
Record your answer with two significant figures.
J/gC?????????????????????????????????????????
Answered by
Breanna Johnson
Uglies
Answered by
:)
The sum is 0.64
Answered by
yessir
0.64 is answer
Answered by
lanayja
THANKS VERY MUCH