Asked by K_A_B

there are 9 candidates running for 3 seats on a committee. how many different election results are possible?
36
84
504
56***
Answered by Astral Tellurian
9!: 9x8x7

This is because they are just using 3 seats. Multiply that and you will get your answer. :)

Of course, you want a quick answer right? Well here is the answer, but I hope you know how to do this afterwards. . .

504
Answered by K_A_B
Ohh ty. I got confused
Answered by Astral Tellurian
No probs, it's pretty easy once you get the hang of it.
Answered by Reiny
You are "choosing" 3 from 9
The answer of 504 represents the number of permutations, that is, there are distinct places.
e.g. ABC is different from BAC

This is a combination question

number of ways to choose 3 from 9
= C(9,3)
= 84

C(9,3) = 9!/(3!6!)
Answered by R5er
Reiny is correct
Answered by anonymous
what is the equation!!!!!!!!!!!! please tell mee !!!!!!!!!!!
Answered by Anonymous
I understand how you get to 504, but how do you get to 84? Can someone, please help me it would mean a lot!
Answered by pheemer
im a little late, but the equation reiny showed was 9 factorial divided by 3 factorial * 6 factorial.
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