Question

A MACHINE OF EFFICIENCY 60% IS USED TO RAISE A LOAD OF 150kg THROUGH A VERTICAL DISTANCE OF 2.5m.CALCULATE THE WORK DONE [IN JOULES]. I tried E=WORK OUTUT/WORK INPUT times 100% 60=150 times 10 times 2.5/work input times 100 60 times work input=3750 times 100 work input=375000/60 work done=6250J

Answer 1

Wo = F*d=M*g * d = 150*9.8 * 2.5
= 3675 J. = Work output or work done.

Input = 3675/0.6, but it did not ask for the input.

Answer 2

Yes