Asked by Angela
A machine of efficiency 80% is used to raise a load of body of mass 75kg through a vertical height of 3m in 30seconds.Calculate the power input.
Answers
Answered by
Chanz
P = W/t = mgh/t = 75*9.8*3/30
80% eff means divide above by 0.8
80% eff means divide above by 0.8
Answered by
DhayZ
E=Work done/txinput x100
80=75*10*3*100/30input
Cross multiply
80x30input =225000
2400input =225000
Input =225000/2400
Input =93.75
80=75*10*3*100/30input
Cross multiply
80x30input =225000
2400input =225000
Input =225000/2400
Input =93.75
Answered by
Courage
An inclined plane of angle 15is used of 2m .if the plane is 75% efficiency calculate the velocity ration of the plane and work done on the load
Answered by
Emmanuel Nuwanyea
Yes
Answered by
Emmanuel Nuwanyea
Yes that's the question
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