Asked by Anonymous

The efficiency of a machine is 80%. Determine the work done by a person using this machine to raise a load of 200kg through a vertical distance of 3.0 (take g = 10m/s)
Answered by Henry
F = M*g = 200 * 10 = 2000 N.

Work = F*d/0.8 = 2000 * 3/0.8 =
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7500Joules
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7500 joules
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7500
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7500
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7500
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