Hi I need help with this problem full solution only please: Two angles of a triangle have the same measure and the third one is 9 degrees greater than the measure of each of the other two. Find the measure of the LARGEST angle in the triangle.

2 answers

in a triangle the sum of all angles = 180
ie., x+y+z=180 -(1)
suppose y=z
and x= 9+y or 9+z
ie.,
than (1) becomes
9+y+y+z=180
as y=z
9+y+y+y=180
9+3y=180
3y=180-9
y=180-9/3

there u get y put in x= 9+y u get the largest angle x
Angle #1 = X Deg.
Angle #2 = X Deg.
Angle #3 = (X+9) Deg.

x + x + x+9 = 180 Deg.
3x = 171.
X = 57o

x+9 = 57+9 = 66o = Largest angle.
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