Asked by James
A solution is prepared by adding 1.50 mol glucose to 3.50 mol water. What is the vapor pressure of the solution at 25 oC given that the vapor pressure of pure water is 23.8 torr?
Answers
Answered by
DrBob222
mols glucose = 1.50
mols water = 3.50
total mols = 1.50 + 3.50 = ?
X(mol fraction) H2O = mols water/total mols.
P<sub>solution</sub> = X<sub>solvent</sub>*P<sup>o</sup> <sub>solvent</sub>
mols water = 3.50
total mols = 1.50 + 3.50 = ?
X(mol fraction) H2O = mols water/total mols.
P<sub>solution</sub> = X<sub>solvent</sub>*P<sup>o</sup> <sub>solvent</sub>
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