Asked by Tia
A solution is prepared by adding of KOH to 1 liter of water. The resulting solution has an [OH negative]of 1 * 10 negative 3. What would be the pOH of this solution?
Can you show me how you came up with this answer? Thank you.
Can you show me how you came up with this answer? Thank you.
Answers
Answered by
DrBob222
KOH is a strong base; it ionizes 100%.
KOH ==> K^+ + OH^-
The problem states that (OH^-) = 1E-3.
pOH = -log(OH^-)
pOH = -log(1E-3)
pOH = -(-3)
pOH = 3.
KOH ==> K^+ + OH^-
The problem states that (OH^-) = 1E-3.
pOH = -log(OH^-)
pOH = -log(1E-3)
pOH = -(-3)
pOH = 3.
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