Asked by Carla M
A solution is prepared by adding of KOH to 1 liter of water. The resulting solution has an [OH] of 1*10 to the negative 3. What would be the pOH of this solution?
Answers
Answered by
Anonymous
[OH-] = 1*10 to the negative 3
pOH = -log(1*10 to the negative 3)
pOH = -log(1*10 to the negative 3)
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