Asked by TayB
                Sketch the region enclosed by the given curves. Find its area.
y=7cos pi x, y=12x^2-3
            
        y=7cos pi x, y=12x^2-3
Answers
                    Answered by
            Steve
            
    See
http://www.wolframalpha.com/input/?i=plot+y%3Dcos%28pi*x%29%2C+y%3D12x^2-3
the curves intersect at (-1/2,0) and (1/2,0).
So, it's just a straightforward integral. Since things are symmetric, the area is just
2∫[0,1/2] cos(πx)-(12x^2-3) dx
    
http://www.wolframalpha.com/input/?i=plot+y%3Dcos%28pi*x%29%2C+y%3D12x^2-3
the curves intersect at (-1/2,0) and (1/2,0).
So, it's just a straightforward integral. Since things are symmetric, the area is just
2∫[0,1/2] cos(πx)-(12x^2-3) dx
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.