Asked by LAUERN PLEASE HELP
Sketch the region enclosed by the given curves.
y = tan 3x, y = 2 sin 3x, −π/9 ≤ x ≤ π/9
then then find the area.
i can sketch but cant find correct area
y = tan 3x, y = 2 sin 3x, −π/9 ≤ x ≤ π/9
then then find the area.
i can sketch but cant find correct area
Answers
Answered by
Steve
algebraically, since both functions are symmetric about the origin, the area is zero.
geometrically, using symmetry, you have the area is
2∫[0,pi/9] (tan3x - 2sin3x) dx
= 2/3 (2cos 3x - log cos 3x)[0,pi/9]
= 2/3 (log2 - 1)
geometrically, using symmetry, you have the area is
2∫[0,pi/9] (tan3x - 2sin3x) dx
= 2/3 (2cos 3x - log cos 3x)[0,pi/9]
= 2/3 (log2 - 1)
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