Sketch the region enclosed by the given curves.
y = 4/X
y = 16x, y = 1X/16
x > 0
and the area between the curves

Answers

Answered by bobpursley
Can you sketch the curves?
Answered by LAUERN PLEASE HELP
yes i just need the area i didn't know how to sketch it on here
Answered by Steve
If I read it correctly, you have
y=4/x, y=16x, and y=x/16 for x>0

You need to break the area into two regions, because the two top curves intersect at x = 1/2

So the area is

∫[0,1/2] 16x - x/16 dx + ∫[1/2,8] 4/x - x/16 dx
= (8x^2-x^2/32)[0,1/2] + (4logx-x^2/32)[1/2,8]
= 255/128 + (4log16 - 255/128)
= 4log16 = 16log2
Answered by LAUERN PLEASE HELP
thank you!
Answered by LAUERN PLEASE HELP
or that's not right
Answered by Court
change the 16log(2) to 16ln(2) and then the answer is correct.
Answered by marta
excellent! thanks a lot!
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