Asked by LAUERN PLEASE HELP
Sketch the region enclosed by the given curves.
y = 4/X
y = 16x, y = 1X/16
x > 0
and the area between the curves
y = 4/X
y = 16x, y = 1X/16
x > 0
and the area between the curves
Answers
Answered by
bobpursley
Can you sketch the curves?
Answered by
LAUERN PLEASE HELP
yes i just need the area i didn't know how to sketch it on here
Answered by
Steve
If I read it correctly, you have
y=4/x, y=16x, and y=x/16 for x>0
You need to break the area into two regions, because the two top curves intersect at x = 1/2
So the area is
∫[0,1/2] 16x - x/16 dx + ∫[1/2,8] 4/x - x/16 dx
= (8x^2-x^2/32)[0,1/2] + (4logx-x^2/32)[1/2,8]
= 255/128 + (4log16 - 255/128)
= 4log16 = 16log2
y=4/x, y=16x, and y=x/16 for x>0
You need to break the area into two regions, because the two top curves intersect at x = 1/2
So the area is
∫[0,1/2] 16x - x/16 dx + ∫[1/2,8] 4/x - x/16 dx
= (8x^2-x^2/32)[0,1/2] + (4logx-x^2/32)[1/2,8]
= 255/128 + (4log16 - 255/128)
= 4log16 = 16log2
Answered by
LAUERN PLEASE HELP
thank you!
Answered by
LAUERN PLEASE HELP
or that's not right
Answered by
Court
change the 16log(2) to 16ln(2) and then the answer is correct.
Answered by
marta
excellent! thanks a lot!
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