Asked by HAKEEM

A block and tacle of 6 pulley is used to raise a load of 300n steadily through a height of 30m if the workdone against friction is 2000j. calculate the workdone by the effort,the applied effort,the efficiency of the system

Answers

Answered by Damon
work accomplished = 300*30
= 9,000 J

applied work = 9,000 + 2,000 = 11,000 Joules

efficiency = 100 * work accomplished/work applied

= (9/11)100 = 81.8 %

force applied = (300/6)/.818
= 61.1 N
assuming that the 6 in your question refers to mechanical advantage
Answered by Ruth
Yes
Answered by Noel
Explain pls
Answered by Fatima
Yes
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