Asked by HAKEEM
A block and tacle of 6 pulley is used to raise a load of 300n steadily through a height of 30m if the workdone against friction is 2000j. calculate the workdone by the effort,the applied effort,the efficiency of the system
Answers
Answered by
Damon
work accomplished = 300*30
= 9,000 J
applied work = 9,000 + 2,000 = 11,000 Joules
efficiency = 100 * work accomplished/work applied
= (9/11)100 = 81.8 %
force applied = (300/6)/.818
= 61.1 N
assuming that the 6 in your question refers to mechanical advantage
= 9,000 J
applied work = 9,000 + 2,000 = 11,000 Joules
efficiency = 100 * work accomplished/work applied
= (9/11)100 = 81.8 %
force applied = (300/6)/.818
= 61.1 N
assuming that the 6 in your question refers to mechanical advantage
Answered by
Ruth
Yes
Answered by
Noel
Explain pls
Answered by
Fatima
Yes
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.