A block and tacle of 6 pulley is used to raise a load of 300n steadily through a height of 30m if the workdone against friction is 2000j. calculate the workdone by the effort,the applied effort,the efficiency of the system

Answer 1

work accomplished = 300*30
= 9,000 J

applied work = 9,000 + 2,000 = 11,000 Joules

efficiency = 100 * work accomplished/work applied

= (9/11)100 = 81.8 %

force applied = (300/6)/.818
= 61.1 N
assuming that the 6 in your question refers to mechanical advantage

Answer 2

Yes

Answer 3

Explain pls

Answer 4

Yes