Asked by Anonymous
A block and tackle of 6 pulley is used to raise a load of 30N steadily through a height of 3m. If the work done against friction is 100J and the total work done by the effort is 500J. Calculate:
a. The work done to raise the load
b. The efficiency of the system
c. The applied effort
a. The work done to raise the load
b. The efficiency of the system
c. The applied effort
Answers
Answered by
Anonymous
work output is load weight * height raised = 30 N * 3 m = 90 Joules
work wasted in friction = 100 Joules
work input = 90 + 100 = 190 Joules
efficiency = 100 * work output / work input = 100 (90/190) = 47.4 %
If applied effort is the force in it is 1/6 * 190/3 = 10.6 Newtons
work wasted in friction = 100 Joules
work input = 90 + 100 = 190 Joules
efficiency = 100 * work output / work input = 100 (90/190) = 47.4 %
If applied effort is the force in it is 1/6 * 190/3 = 10.6 Newtons
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