Asked by Wayne
Vehicle A is 819.017 feet behind vehicle B. Vehicle A is traveling at 93.602fps and vehicle B is traveling at 44fps. How long until vehicle A catches vehicle B?
Answers
Answered by
Reiny
so the 2nd vehicle must make up the distance of 819.017 ft
let the time taken to catch up be t seconds
93.602t - 44t = 819.017
solve for t
let the time taken to catch up be t seconds
93.602t - 44t = 819.017
solve for t
Answered by
Damon
in time t
vehicle A travels distance d
vehicle B travels distance (d-819.017)
93.602 t = d
44 t = d-819.017
so
44 t = 93.602 t -819.017
vehicle A travels distance d
vehicle B travels distance (d-819.017)
93.602 t = d
44 t = d-819.017
so
44 t = 93.602 t -819.017
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