Question
If a vehicle travels 1320 feet in seven seconds from a dead stop , how long does it take for that same vehicle to travel 1313 feet from a dead stop ?
Answers
Steve
7s/1320ft * 1313ft = 6.96 s
assuming instant change in velocity.
Assuming a constant acceleration,
1/2 a*49 = 1320, so
a = 53.877 ft/s^2
Now, to get 1313 ft using the same acceleration, we have
53.877/2 t^2 = 1313
t = 6.98 s
assuming instant change in velocity.
Assuming a constant acceleration,
1/2 a*49 = 1320, so
a = 53.877 ft/s^2
Now, to get 1313 ft using the same acceleration, we have
53.877/2 t^2 = 1313
t = 6.98 s