Question
Mass m1 on the frictionless table of the figure below is connected by a string through a hole in the table to a hanging mass m2. With what speed must m1 rotate in a circle of radius r if m2 is to remain hanging at rest? (Use any variable or symbol stated above along with the following as necessary: g.)
Answers
m2 g = m1 v^2/r
Fm1=(m1v^2)/r
Fm2=mg=9.8m2
Rewrite Fm1=(m1v^2)/r as v= sqrt Fr/sqrt m1
Plug Fm2 into the equation to get: sqrt 9.8m2r/sqrt m1
Fm2=mg=9.8m2
Rewrite Fm1=(m1v^2)/r as v= sqrt Fr/sqrt m1
Plug Fm2 into the equation to get: sqrt 9.8m2r/sqrt m1
v=sqrt (m2(g)(r))/m1
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