Asked by dele Japhet
A current of 5A was passed through a solution of nickel (1)(1))salt.find the time taken for 6g of nickel to be deposited
Answers
Answered by
Damon
Oh my. How many electrons?
Nickel is 58.7 grams per mole or 6*10^23 atoms which here is 6*10^23 electros
so
6 g * 6.022*10^23 electrons/58.7 g
= .6155 * 10^23 electrons
1.602*10^-19 coulomb/electron
so the product is
.986 * 10^4 Coulombs
a coulomb is an amp second
so
.986*10^4 = 5 t
t = .197 * 10^4 seconds
= 1970 seconds
= about 33 minutes
check my algebra !
Nickel is 58.7 grams per mole or 6*10^23 atoms which here is 6*10^23 electros
so
6 g * 6.022*10^23 electrons/58.7 g
= .6155 * 10^23 electrons
1.602*10^-19 coulomb/electron
so the product is
.986 * 10^4 Coulombs
a coulomb is an amp second
so
.986*10^4 = 5 t
t = .197 * 10^4 seconds
= 1970 seconds
= about 33 minutes
check my algebra !
Answered by
Jamiu Yusuf
Excellent
Answered by
deborah
how did u get the answers
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