Question
A current of 4.00 A is passed through a solution of AgNO3 for 1.00 hr. What mass of silver is deposited at the cathode? (In grams)
Use Faraday's constant F = 9.65x10^4 C/mol
Use Faraday's constant F = 9.65x10^4 C/mol
Answers
DrBob222
C = amperes x seconds
C = 4.00 x 1 hr x (60 min/hr) x (60 s/min) = ?
96,500 C will deposit 107.9 g Ag.
107.9 g Ag x (? C from above)/96,500 = ? g Ag deposited.
C = 4.00 x 1 hr x (60 min/hr) x (60 s/min) = ?
96,500 C will deposit 107.9 g Ag.
107.9 g Ag x (? C from above)/96,500 = ? g Ag deposited.
Ahead
0.5556
.....
9.05 g