Asked by Anon

A current of 4.60 A is passed through a Pb(NO3)2 solution for 1.20 hours. How much lead is plated out of the solution?
Answered by DrBob222
Coulombs = amp x 1.2 hr x (60 min/hr)(60 sec/min) = estimated 20,000 C.
96,485 C will plate out 207.2/2 grams Pb(about 104 g) so
(207.2/2) x (20,000/96,485) = g Pb plated out. Remember to correct the value for C; 20000 is just an estimate.
Answered by Anonymous
1.25
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