Asked by Henry
Which of the following integrals cannot be evaluated using a simple substitution?
I think it is A because if you would substitute there would be nothing left in the equation? Is that right?
Options
∫√(x-1)
∫1/√(1-x^2)
∫x/√(1-x^2)
∫√(x^2-1)
I think it is A because if you would substitute there would be nothing left in the equation? Is that right?
Options
∫√(x-1)
∫1/√(1-x^2)
∫x/√(1-x^2)
∫√(x^2-1)
Answers
Answered by
Damon
A.
let y = x-1
dy = dx
∫√(x-1) = ∫y^.5 dy
that works
let y = x-1
dy = dx
∫√(x-1) = ∫y^.5 dy
that works
Answered by
Henry
Wait so A is right or is it wrong?
Answered by
Damon
B.
let y = 1 - x^2
dy = -2 x dx
∫1/√(1-x^2) dx = ∫y^-.5 dy/(-2x)
very awkward
Hey be sure to include the dx in your integrals
C will be easy because the x in -2xdx cancels
let y = 1 - x^2
dy = -2 x dx
∫1/√(1-x^2) dx = ∫y^-.5 dy/(-2x)
very awkward
Hey be sure to include the dx in your integrals
C will be easy because the x in -2xdx cancels
Answered by
Damon
You are wrong. A CAN easily be solved
Be sure to include the dx in your integrals so you include it when you substitute
Be sure to include the dx in your integrals so you include it when you substitute
Answered by
Henry
Okay will do. So I'm presuming your saying the answer is B. I think D works.
Answered by
Damon
∫√(x^2-1) dx <---- NOTE that dx
let y = x^2-1
then dy = 2 x dx so dx = dy/2x
∫√(x^2-1) DX =∫y^.5 dy/2x
a mess again
let y = x^2-1
then dy = 2 x dx so dx = dy/2x
∫√(x^2-1) DX =∫y^.5 dy/2x
a mess again
Answered by
Damon
I had trouble with B and D
Answered by
Damon
the problem with B and D is that
dx = dy/f(x)
so the substitution does not get rid of the x
dx = dy/f(x)
so the substitution does not get rid of the x
Answered by
Damon
In C, that nasty x cancels
Answered by
Henry
Okay Thanks. That one confused me.
Answered by
Henry
Im think im going to go with B then
Answered by
Damon
B and D
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