Asked by KAZIN BONNY
A block of wood has a mass of 3.6kg and specific gravity of 0.6. It is to be loaded with lead of density of 11300 kg per cubic metre so that it floats in water with 0.90 of its volume immersed. What mass of lead is needed?
(a) if the lead is on top of the wood?
(b) if the lead is attached below the wood?
(a) if the lead is on top of the wood?
(b) if the lead is attached below the wood?
Answers
Answered by
bobpursley
a. if it is on top, then the water displaced is
densitywater*volume*.9, which must equal at the mass of lead+masswood.
masslead=-masswood+densitywater*volume*.9
but mass wood=volume*densitywood
masslead=masswood+densitywater*masswood* .9/densitywood
solve for masslead.
densitywater*volume*.9, which must equal at the mass of lead+masswood.
masslead=-masswood+densitywater*volume*.9
but mass wood=volume*densitywood
masslead=masswood+densitywater*masswood* .9/densitywood
solve for masslead.
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