Asked by Sam
A block of wood of mass 1.2kg initially at rest is free to slide on a horizontal surface. A bullet of mass 100g travelling at a speed of 780ms^-1 is fired horizontally at the block and becomes embedded in it. Calculate the speed the block and bullet move off at immediately after the collision.
Answers
Answered by
bobpursley
conservation of momentum
massbullet*velocitybullet=(massbullet+massblock)V
solve for V
massbullet*velocitybullet=(massbullet+massblock)V
solve for V
Answered by
Mat
v=1.67
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