Question
A block of wood of mass 1.2kg initially at rest is free to slide on a horizontal surface. A bullet of mass 100g travelling at a speed of 780ms^-1 is fired horizontally at the block and becomes embedded in it. Calculate the speed the block and bullet move off at immediately after the collision.
Answers
bobpursley
conservation of momentum
massbullet*velocitybullet=(massbullet+massblock)V
solve for V
massbullet*velocitybullet=(massbullet+massblock)V
solve for V
Mat
v=1.67