Question

A block of wood with a mass of 4.62 kg sits on the edge of a table that is 0.99 m tall. A bullet with a mass of 70.5 g traveling with a speed of 450 m/s is shot into the block and is lodged in it. Assuming that no energy is lost to friction, how far from the table will the block land?
conservation of momentum applies to the block/bullet.

MbVb=(Mb+Mblock)Vf

now find out how much time it takes to fall .99m
Then, distance=Vf*timetofall

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